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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented using the equation [tex]p = 10000(1.04)^{-t}[/tex]. Which of the following is an equivalent expression?

A. [tex]p = 10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p = 10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p = 10000\left(\frac{26}{25}\right)^t[/tex]

D. [tex]p = 10000\left(\frac{25}{1}\right)^t[/tex]

Answer :

We start with the given equation:

[tex]$$
p = 10000(1.04)^{-t}.
$$[/tex]

Recall that raising a number to a negative exponent is equivalent to taking the reciprocal raised to the positive exponent. That is,

[tex]$$
(1.04)^{-t} = \left(\frac{1}{1.04}\right)^t.
$$[/tex]

Next, we express [tex]$1.04$[/tex] as a fraction. Notice that

[tex]$$
1.04 = \frac{26}{25}.
$$[/tex]

Taking the reciprocal gives:

[tex]$$
\frac{1}{1.04} = \frac{1}{\frac{26}{25}} = \frac{25}{26}.
$$[/tex]

Substitute this back into the equation:

[tex]$$
p = 10000\left(\frac{25}{26}\right)^t.
$$[/tex]

Thus, the equivalent expression is

[tex]\[
p = 10000\left(\frac{25}{26}\right)^t,
\][/tex]

which corresponds to the second option.

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