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Prove that a quadrilateral is a parallelogram.

In quadrilateral [tex]WXYZ[/tex], [tex]WC = 2x + 5[/tex] and [tex]CY = 3x + 2[/tex]. What must [tex]x[/tex] equal for quadrilateral [tex]WXYZ[/tex] to be a parallelogram?

[tex]x = \square[/tex]

Answer :

To find the value of [tex]\( x \)[/tex] that makes quadrilateral [tex]\( WXYZ \)[/tex] a parallelogram, we need to understand that in a parallelogram, opposite sides are equal. Since [tex]\( WC \)[/tex] and [tex]\( CY \)[/tex] are given as expressions for parts of opposite sides, they must be equal for [tex]\( WXYZ \)[/tex] to be a parallelogram.

Given:
- [tex]\( WC = 2x + 5 \)[/tex]
- [tex]\( CY = 3x + 2 \)[/tex]

Since [tex]\( WC \)[/tex] and [tex]\( CY \)[/tex] are opposite sides of the parallelogram, they must be equal.

Set the expressions equal to each other:
[tex]\[ 2x + 5 = 3x + 2 \][/tex]

Now solve for [tex]\( x \)[/tex]:

1. Subtract [tex]\( 2x \)[/tex] from both sides:
[tex]\[ 5 = x + 2 \][/tex]

2. Subtract 2 from both sides:
[tex]\[ 3 = x \][/tex]

So, [tex]\( x = 3 \)[/tex].

Therefore, the value of [tex]\( x \)[/tex] that makes the quadrilateral [tex]\( WXYZ \)[/tex] a parallelogram is [tex]\( x = 3 \)[/tex].

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