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Answer :
To perform a one-sample z test for a proportion, the Large Counts condition requires that the numbers [tex]$np$[/tex] and [tex]$n(1-p)$[/tex] are both sufficiently large (usually at least 10). This condition ensures that the sampling distribution of the sample proportion is approximately Normal. In other words, it is used to verify that the use of the Normal approximation (via the Central Limit Theorem) is valid for the proportion.
Thus, the purpose of checking the Large Counts condition is to ensure that
[tex]$$
\text{the sampling distribution of } p \text{ is approximately Normal},
$$[/tex]
which corresponds to option (c).
Thus, the purpose of checking the Large Counts condition is to ensure that
[tex]$$
\text{the sampling distribution of } p \text{ is approximately Normal},
$$[/tex]
which corresponds to option (c).
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