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Select the correct answer.

Justine enrolls in a music program. The cost of the program includes a one-time registration fee of [tex]\$45[/tex] and a fee of [tex]\$9[/tex] per lesson. If the average cost per music lesson is [tex]\$12[/tex] and Justine has taken [tex]x[/tex] classes, which equation represents this scenario?

A. [tex]12=\frac{54}{2}[/tex]

B. [tex]12=45+\frac{9}{z}[/tex]

C. [tex]12=\frac{45+9z}{z}[/tex]

D. [tex]12=\frac{45z+9}{z}[/tex]

Answer :

Great question! Let's break it down step-by-step to find which equation represents Justine’s scenario.

1. Understanding the Problem:
- Justine pays a one-time registration fee of \[tex]$45.
- She also pays a fee of \$[/tex]9 per lesson.
- The average cost per music lesson is \[tex]$12.
- She has taken \( z \) (let’s use \( z \) instead of \( x \) to match the question's terminology) lessons.

2. Setting Up the Scenario:
- The total cost Justine pays after \( z \) lessons is the sum of the registration fee and the cost for \( z \) lessons.

Total cost = Registration fee + (Fee per lesson × Number of lessons)

So, the total cost \( T \) is:
\[
T = 45 + 9z
\]

3. Average Cost per Lesson:
- The average cost per lesson is the total cost divided by the number of lessons.
\[
\text{Average cost per lesson} = \frac{T}{z} = \frac{45 + 9z}{z}
\]

4. Given Information:
- We know the average cost per lesson is \$[/tex]12.

Therefore, we set up the equation:
[tex]\[
12 = \frac{45 + 9z}{z}
\][/tex]

Now, we match this with the given options:

A. [tex]\( 12 = \frac{54}{2} \)[/tex]
- This does not relate to our scenario and is incorrect.

B. [tex]\( 12 = 45 + \frac{9}{z} \)[/tex]
- This also doesn’t match our equation and is incorrect.

C. [tex]\( 12 = \frac{45 + 9z}{z} \)[/tex]
- This is exactly what we derived and is correct.

D. [tex]\( 12 = \frac{45z + 9}{z} \)[/tex]
- This is not correct as it doesn’t represent the relationship correctly.

So, the correct answer is:
[tex]\[
\boxed{C}
\][/tex]

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