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Two horses start pulling a 412 kg wagon from rest. One horse exerts 193 N, and the other exerts 207 N. Both horses pull in the same direction.

Ignoring friction, how fast is the wagon moving 5.68 seconds later?

Answer :

Final answer:

The speed of the wagon after 5.68 seconds is approximately 5.519 m/s. This is calculated using Newton's Second Law of Motion, dividing the total force exerted by the mass of the wagon to find the acceleration, then multiplying the acceleration by the time duration.

Explanation:

The problem here can be solved by using Newton's Second Law of Motion which states that the acceleration of an object is directly proportional to the net force exerted on it and inversely proportional to its mass. In this case, the net force exerted on the wagon is the total force that both horses apply which is 193 N + 207 N = 400 N. So, the acceleration of the wagon is the net force divided by the mass: 400 N / 412 kg = 0.971 m/s².

Then, we can use the formula for velocity which is the acceleration multiplied by the time duration. Applying the numbers: 0.971 m/s² * 5.68 s = 5.519 m/s. Therefore, the wagon will be moving at an approximate speed of 5.519 m/s after 5.68 s, ignoring friction.

Learn more about Newton's Second Law of Motion here:

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