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A solar panel measures 0.57 m by 1.3 m. In direct sunlight, the panel delivers 6.6 A at 6 V. If the intensity of sunlight is 300 W/m², what is the efficiency, as a percentage, of the solar panel in converting solar energy into electrical energy?

Answer :

Answer:

efficiency of solar panel is 18%

Explanation:

Energy received by the sunlight is given as

[tex]Power = intensity \times area[/tex]

here we know the dimensions of the plate as

[tex]L = 0.57 m[/tex]

[tex]W = 1.3 m[/tex]

now we have

[tex]Area = (0.57)(1.3) m^2[/tex]

[tex]A = 0.741 m^2[/tex]

now the power received by the sun light is given as

[tex]P_1 = 0.741(300) = 222.3 W[/tex]

now the output power due to solar panel is given as

[tex]P_{out} = V i[/tex]

[tex]P_{out} = (6.6 A)(6 V)[/tex]

[tex]P_{out} = 39.6 Watt[/tex]

now the efficiency is given as

[tex]\eta = \frac{P_{out}}{P_{in}}[/tex]

[tex]\eta = \frac{39.6}{222.3}[/tex]

[tex]\eta = 0.18[/tex]

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Rewritten by : Barada