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Given the sequence [tex]-5 \frac{1}{3}, -10 \frac{2}{3}, -21 \frac{1}{3}, -42 \frac{2}{3}, \ldots[/tex], which formula can be used to describe it?

A. [tex]f(x+1) = -2 f(x)[/tex]

B. [tex]f(x+1) = -\frac{1}{2} f(x)[/tex]

C. [tex]f(x+4) = \frac{1}{2} f(x)[/tex]

D. [tex]f(x+1) = 2 f(x)[/tex]

Answer :

We start with the sequence:
[tex]$$-5 \tfrac{1}{3},\quad -10 \tfrac{2}{3},\quad -21 \tfrac{1}{3},\quad -42 \tfrac{2}{3},\quad \ldots$$[/tex]

Step 1. Convert mixed numbers to improper fractions.

For the first term:
[tex]$$-5 \tfrac{1}{3} = -\frac{(5 \times 3 + 1)}{3} = -\frac{16}{3}.$$[/tex]

For the second term:
[tex]$$-10 \tfrac{2}{3} = -\frac{(10 \times 3 + 2)}{3} = -\frac{32}{3}.$$[/tex]

For the third term:
[tex]$$-21 \tfrac{1}{3} = -\frac{(21 \times 3 + 1)}{3} = -\frac{64}{3}.$$[/tex]

For the fourth term:
[tex]$$-42 \tfrac{2}{3} = -\frac{(42 \times 3 + 2)}{3} = -\frac{128}{3}.$$[/tex]

Thus, the sequence in improper fraction form is:
[tex]$$-\frac{16}{3},\quad -\frac{32}{3},\quad -\frac{64}{3},\quad -\frac{128}{3},\quad \ldots$$[/tex]

Step 2. Identify the pattern.

Notice that each term is obtained by multiplying the previous term by 2:
[tex]$$-\frac{16}{3} \times 2 = -\frac{32}{3},$$[/tex]
[tex]$$-\frac{32}{3} \times 2 = -\frac{64}{3},$$[/tex]
[tex]$$-\frac{64}{3} \times 2 = -\frac{128}{3}.$$[/tex]

Thus, the relationship between consecutive terms is given by:
[tex]$$f(n+1) = 2 \, f(n).$$[/tex]

Step 3. Conclude the appropriate formula.

From the options provided, the recurrence relation corresponding to the pattern is:
[tex]$$f(x+1)=2 f(x).$$[/tex]

Therefore, the correct formula is:

[tex]$$\boxed{f(x+1)=2 f(x)}.$$[/tex]

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