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Find the resistance of a copper wire that is 25.0 m long with a cross-sectional area of [tex]7.45 \times 10^{-3} \text{ cm}^2[/tex] at 21°C. The resistivity of copper at 21°C is [tex]1.69 \times 10^{-6} \Omega \cdot \text{cm}[/tex].

Answer :

Final answer:

The resistance of the copper wire is 5.72 Ω.


Explanation:

Resistance is a property that opposes the flow of electric current. It can be calculated using the formula R = (ρ * L) / A, where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

In this case, the resistivity of copper is given as 1.69 x 10-6 Ω cm and the length of the wire is 25.0 m. However, the given cross-sectional area is in cm², so it needs to be converted to m². 1 cm² is equal to 10-4 m², so the cross-sectional area is 7.45 x 10-7 m².

Plugging in these values into the formula, we get: R = (1.69 x 10-6 Ω cm * 25.0 m) / (7.45 x 10-7 m²) = 5.72 Ω.


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