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If it cost [tex]\$3[/tex] to fill a gas tank in 1960, how much of the same tank could be filled with [tex]\$3[/tex] in 1970?

\begin{tabular}{|l|c|c|c|}
\hline
Year & Price & \begin{tabular}{c}Price as a Percentage \\ of 1980 Price\end{tabular} & \begin{tabular}{c}Price Index \\ (1980=100)\end{tabular} \\
\hline
1960 & [tex]\$0.31[/tex] & 25.4\% & 25.4 \\
1970 & [tex]\$0.36[/tex] & 29.5\% & 29.5 \\
1980 & [tex]\$1.22[/tex] & 100.0\% & 100.0 \\
1990 & [tex]\$1.23[/tex] & 100.8\% & 100.8 \\
2000 & [tex]\$1.56[/tex] & 127.9\% & 127.9 \\
2010 & [tex]\$2.84[/tex] & 232.8\% & 232.8 \\
\hline
\end{tabular}

About [tex]\square[/tex] of the same tank could be filled.

Answer :

Sure! Let's work through this problem step-by-step to determine how much of the same tank could be filled with [tex]$3 in 1970.

1. Understand the problem:
We are asked how much gasoline $[/tex]3 could buy in 1970, given historical gas prices.

2. Identify the relevant prices:
- In 1960, the price of gasoline was [tex]$0.31 per gallon.
- In 1970, the price of gasoline was $[/tex]0.36 per gallon.

3. Calculate how many gallons [tex]$3 could buy in 1970:
We need to determine how many gallons of gasoline $[/tex]3 could purchase in 1970 if each gallon costs [tex]$0.36.

4. Set up the calculation:
To find the number of gallons we can buy, use the formula:
\[
\text{Number of gallons} = \frac{\text{Total amount of money}}{\text{Price per gallon}}
\]
In this case:
\[
\text{Number of gallons} = \frac{3 \text{ dollars}}{0.36 \text{ dollars per gallon}}
\]

5. Perform the division:
When we divide $[/tex]3 by [tex]$0.36, we get:
\[
\text{Number of gallons} = 8.\overline{3}
\]

So, $[/tex]3 could fill approximately [tex]\( 8.33 \)[/tex] gallons of gasoline in 1970.

Therefore, with $3 in 1970, you could fill about 8.33 gallons of the same tank.

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