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Solve the equation:

[tex] 9x^7 - 1 = 0 [/tex]

Answer :

To solve the equation [tex]\(9x^7 - 1 = 0\)[/tex], we want to find the values of [tex]\(x\)[/tex] that make the equation equal to zero.

Here are the steps to solve the equation:

1. Equation Setup:

Start with the given equation:
[tex]\[
9x^7 - 1 = 0
\][/tex]

2. Isolate the Power Term:

Add 1 to both sides to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[
9x^7 = 1
\][/tex]

3. Divide by 9:

Divide both sides by 9 to solve for [tex]\(x^7\)[/tex]:
[tex]\[
x^7 = \frac{1}{9}
\][/tex]

4. Take the Seventh Root:

To solve for [tex]\(x\)[/tex], take the seventh root of both sides. This will result in:
[tex]\[
x = \left(\frac{1}{9}\right)^{1/7}
\][/tex]

5. Complex Roots:

When solving for the seventh roots, we take into consideration that there are 7 distinct roots (one real and six complex). These correspond to the values:
- The real root: [tex]\( x = 3^{5/7}/3 \)[/tex]

- The complex roots, which are obtained using the formulas involving trigonometric expressions (cosine and sine terms), taking into account the angles distributed over a circle, which relate to the roots of unity. These complex roots are:
[tex]\[
x = -\frac{3^{5/7}}{3} \left(\cos\left(\frac{\pi}{7}\right) + i\sin\left(\frac{\pi}{7}\right)\right)
\][/tex]
[tex]\[
x = -\frac{3^{5/7}}{3} \left(\cos\left(\frac{\pi}{7}\right) - i\sin\left(\frac{\pi}{7}\right)\right)
\][/tex]
[tex]\[
x = \frac{3^{5/7}}{3} \left(\cos\left(\frac{2\pi}{7}\right) - i\sin\left(\frac{2\pi}{7}\right)\right)
\][/tex]
[tex]\[
x = \frac{3^{5/7}}{3} \left(\cos\left(\frac{2\pi}{7}\right) + i\sin\left(\frac{2\pi}{7}\right)\right)
\][/tex]
[tex]\[
x = -\frac{3^{5/7}}{3} \left(\cos\left(\frac{3\pi}{7}\right) + i\sin\left(\frac{3\pi}{7}\right)\right)
\][/tex]
[tex]\[
x = -\frac{3^{5/7}}{3} \left(\cos\left(\frac{3\pi}{7}\right) - i\sin\left(\frac{3\pi}{7}\right)\right)
\][/tex]

These represent all the solutions for the equation [tex]\(9x^7 - 1 = 0\)[/tex], including both the real and complex roots.

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