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Answer :
Final answer:
The width of the rectangular field is 139 feet and its length is 320 feet.
Explanation:
To solve this problem, we can use the formula for the perimeter of a rectangle, which is 2*(length + width). We know that the perimeter is 918 feet, and it's given that the length is 181 feet more than the width.
Let's denote the width as w, therefore the length would be w + 181.
By substituting these expressions into the formula for the perimeter, we get:
2*(w + w + 181)=918,
which simplifies to 2*(2w + 181)=918,
further simplifies to 4w + 362 = 918.
To isolate 4w, subtract 362 from both sides:
4w = 918 - 362 = 556.
Finally, divide both sides by 4 to solve for w:
w = 556/4 = 139 feet.
Substitute w = 139 into the length equation to get the length:
length = w + 181 = 139 + 181 = 320 feet.
So the width is 139 feet, and the length is 320 feet.
Learn more about Solving for Rectangle Dimensions here:
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Rewritten by : Barada
Length is 320 feet.
Let's define the width of the rectangle as w feet and the length as l feet.
According to the problem,
the perimeter of the rectangle is 918 feet and the length is 181 feet more than the width.
We can express these conditions using the following equations:
Perimeter equation: 2l + 2w = 918
Length equation: l = w + 181
First, we can solve the perimeter equation for l+w:
2l + 2w = 918
Divide both sides by 2:
l + w = 459
Next, we substitute the length equation l = w + 181 into the perimeter equation:
w + 181 + w = 459 Simplify:
2w + 181 = 459
Subtract 181 from both sides:
2w = 278
Divide by 2:
w = 139 feet
Now substitute the width back into the length equation:
l = w + 181
l = 139 + 181
l = 320 feet
So, the width is 139 feet, and the length is 320 feet.
