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Assume that adults have IQ scores that are normally distributed with a mean of 98.3 and a standard deviation of 18.2. Find the first quartile \( Q_1 \), which is the IQ score separating the bottom 25% from the top 75%.

Answer :

The the first quartile Q1​, which is the IQ score separating the bottom​ 25% from the top​ 75% is P(x

How to calculate the first quartile?

A quartile is a type of quantile which divides the number of data points into four parts, or quarters, of more-or-less equal size

Using table, z score=-0.67

(x-mean)/sd=-0.67

(x-98.3)/18.2=-0.67

Simplify the expression by collecting like terms

x-98.3=18.2*(-0.67)

x-98.3=-12.192

x=86.106

Therefore, the first quartile is 86.106

Learn more about quartiles on https://brainly.com/question/24329548

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