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Answer :
Answer: 248.66g
Explanation:
4.3e24 / 6.23e23 = 6.9 mols O2
6.9(18.02*2)=248.66
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To determine the grams for 4.3 x 10²⁴ atoms of O₂, calculate the moles by dividing by Avogadro's number, then multiply by the molar mass of oxygen to find the weight in grams, which is approximately 228.48 grams.
To calculate how many grams equal 4.3 x 10²⁴ atoms of oxygen (O₂), we must first understand the concept of moles. One mole of any substance contains Avogadro's number of particles, which is 6.022 x 10²³. Therefore, to find the number of moles of O₂ represented by 4.3 x 10²⁴ atoms, we divide 4.3 x 10²⁴ by 6.022 x 10²³, which gives us approximately 7.14 moles of oxygen (O₂) atoms.
Given that the molar mass of oxygen gas (O₂) is approximately 32.00 grams per mole, we multiply the number of moles by this molar mass to find the mass in grams. Therefore, 7.14 moles of oxygen gas would weigh approximately 228.48 grams (7.14 moles x 32.00 grams/mole).
