We appreciate your visit to A fireworks show is concerned that the fireworks will explode inside some clouds hovering above the area The clouds are between 900 and 1000 feet. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To calculate how long it takes for a firework launched at 235 feet per second from a platform 50 feet high to reach the lower boundary of the clouds at 900 feet, use the formula t = s/u, where s is displacement and u is initial velocity. The calculated time is approximately 3.617 seconds, which doesn't match any of the provided options. Therefore, answer is option 5 that is None of these choices.
The student's question pertains to the time it will take a firework to reach a cloud hovering between 900 and 1000 feet when launched from a platform 50 feet above the ground at a speed of 235 feet per second. To find the time it takes for the firework to reach the lower boundary of the clouds (900 feet), we need to calculate the time it takes to reach 850 feet (since the firework is launched from a height of 50 feet already above the ground).
Using the formula s = ut + (1/2)at², where s is the displacement, u is the initial velocity, a is the acceleration (due to gravity), and t is the time, we can ignore a since we are only interested in the upwards motion before gravity affects the firework's fall. We can simplify to s = ut because the acceleration due to gravity doesn't play a role until the firework reaches its peak height.
Hence, t = s/u. Substituting the values, we get:
t = 850/235
This simplifies to approximately 3.617 seconds. However, this time is not listed in the multiple-choice options given, which means the answer is option 5 that is None of these choices.
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Answer: It is none of these choices.
Step-by-step explanation:
The real amount of seconds (exact amount of seconds) to reach 900 feet would be 4.0425531899 seconds.
