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bWhat is the direction of the movement of the electrons in the wire and the movement of the anions in the salt bridge?


CuAl


The first arrow represents the movement of electrons and the second arrow represents the movement of anions.


Select one:


From beaker 2 to beaker 1, From beaker 2 to beaker 1



From beaker 1 to beaker 2, From beaker 1 to beaker 2



From beaker 2 to beaker 1, From beaker 1 to beaker 2



From beaker 1 to beaker 2, From beaker 2 to beaker 1

bWhat is the direction of the movement of the electrons in the wire and the movement of the anions in the salt bridge CuAl The

Answer :

From beaker 1 to beaker 2, From beaker 2 to beaker 1 is the direction of the movement of the electrons in the wire and the movement of the anions in the salt bridge.

Consider the procedure occurring in each of the half cells in order to comprehend the function of the salt bridge. The cathode would have a 1 M concentration of a copper salt, such as copper sulphate ([Cu2+] = 1 M; [SO42-] = 1 M), and the anode would have a 1 M concentration of a zinc salt, such as zinc sulphate ([Zn2+] = 1 M; [SO42-] = 1 M), if each half cell started at normal state conditions. It should be noted that the sulphate ion is a spectator ion in both half cells, meaning it is not a participant and does not change throughout the electrochemical reaction. Cu2+ in the cathode reduces as the electrochemical reaction progresses and plates out as copper metal.

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