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A 34.5 kg box initially at rest is pushed 5.30 m along a rough, horizontal floor with a constant applied horizontal force of 145 N. If the coefficient of friction between the box and the floor is 0.300, find the following:

(a) The work done by the applied force.

Answer :

Final answer:

The work done by the applied force on the 34.5 kg box being pushed 5.30 m along a rough, horizontal floor with a constant applied horizontal force of 145 N is 768.5 Joules.

Explanation:

The work done by an applied force is calculated using the formula W = F * d * cos(θ), where W is the work done, F is the force, d is the displacement, and θ is the angle between the direction of force and direction of displacement. In your case, the box is being pushed horizontally with a force of 145 N over a distance of 5.30 m.

Therefore, the work done by the applied force is W = F * d = 145 N * 5.30 m = 768.5 J, assuming θ is 0° because the force and displacement are in the same direction. Hence, the work done by the applied force on the box is 768.5 Joules.

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