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Answer :
Final answer:
To find the final potential difference across the 25-µF capacitor, we can use the fact that the total charge remains constant when capacitors are connected in parallel.
Explanation:
To find the final potential difference across the 25-µF capacitor, we can use the fact that the total charge remains constant when capacitors are connected in parallel. We can use the equation Q = CV to find the charge on the 15-µF capacitor, which is given by Q = (15 × 10-6) × 40 = 0.6 mC. Since the total charge remains constant, the charge on the 25-µF capacitor would also be 0.6 mC. Using the equation V = Q/C, we can find the final potential difference across the 25-µF capacitor: V = (0.6 × 10-3) / 25 × 10-6 = 24 V.
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