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Determine the magnitude of [tex]F[/tex] which will cause the positive x-component of the reaction at bearing [tex]C[/tex] to be [tex]C_x = 69 \, \text{N}[/tex]. The bent rod shown in Figure 1 is supported at [tex]A[/tex], [tex]B[/tex], and [tex]C[/tex] by smooth journal bearings. The bearings are in proper alignment and exert only force reactions on the rod.

Answer :

Final answer:

The magnitude of force (F) that will cause the positive x component of reaction at bearing C to be 69 N is 379.7 N.

Explanation:

To determine the magnitude of force (F) that will cause the positive x component of reaction at bearing C to be 69 N, we need to consider the forces acting on the bent rod.

The x-components of the forces at bearings A and B should cancel out, while the x-component of the force at bearing C should be equal to 69 N.

From the given information, we know that the x-component of the force at bearing A is 91.8 N, the x-component of the force at bearing B is 173.2 N, and the x-component of the force at bearing C is 114.7 N.

Therefore, the magnitude of force (F) can be calculated as:

F = |Ax| + |Bx| + |Cx|

Substituting the values:

F = 91.8 N + 173.2 N + 114.7 N = 379.7 N

Therefore, a force of 379.7 N will cause the positive x component of reaction at bearing C to be 69 N.

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