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Answer :
The volume in liters to get a molarity of 0.350 M NaOH.
To determine the molarity of the NaOH solution, we start by using the balanced chemical equation for the reaction:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
This tells us that 2 moles of NaOH react with 1 mole of H₂SO₄. Next, we calculate the number of moles of H₂SO₄ used:
Moles of H₂SO₄ = Molarity (H₂SO₄) × Volume (L)
= 0.112 M × (39.1 mL / 1000)
= 0.0043792 mol H₂SO₄
According to the balanced equation, the ratio of NaOH to H₂SO₄ is 2:1. Therefore, the moles of NaOH is:
Moles of NaOH = 2 × Moles of H₂SO₄
= 2 × 0.0043792 mol
= 0.0087584 mol NaOH
Finally, we calculate the molarity of the NaOH solution:
Molarity (NaOH) = Moles of NaOH / Volume of NaOH (L)
= 0.0087584 mol / (25.0 mL / 1000)
= 0.350 M NaOH
Therefore, the molarity of the NaOH solution is 0.350 M.
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