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Answer :
If an evaporator has a vapour pressure drop of 10 psig and the low side pressure is 15 psig, pressure at the inlet of the evaporator will be 25 psig
change pressure= low side pressure-pressure drop
change pressure=15-(-10)
change pressure=25 psig
The vapor pressure of a liquid, sometimes referred to as the equilibrium pressure of a vapor above its liquid, is the pressure of the vapor produced by the evaporation of a fluid (or solid) over a sample of the liquid (or solid) in such a closed container (or solid).
Vapor pressure is the term for the force that is produced as liquids evaporate. Three factors commonly have an effect on a vapor press: surface area, intermolecular forces, and temperature. The vapor pressures of molecules change with temperature.
To know more about Vapor Pressure visit : brainly.com/question/14718830
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Final answer:
To find the inlet pressure of the evaporator, you add the pressure drop of 10 psig to the low side pressure of 15 psig, resulting in an inlet pressure of 25 psig. So the correct option is d.
Explanation:
If an evaporator has a pressure drop of 10 psig and the low side pressure is 15 psig, the pressure at the inlet of the evaporator can be calculated by adding the pressure drop to the low side pressure. This is because the pressure drop indicates the amount of pressure lost as the refrigerant moves through the evaporator. Therefore, the inlet pressure would be the sum of the two pressures.
The inlet pressure is the low side pressure plus the pressure drop:
15 psig (low side pressure) + 10 psig (pressure drop) = 25 psig (inlet pressure).
