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A 67 kg soccer player uses 5100 kJ of energy during a 2.0-hour match. What is the average power produced by the soccer player?

Answer :

The average power produced by the soccer player is 710 Watts.

Given the data in the question;

  • Mass of the soccer player; [tex]m = 67kg[/tex]
  • Energy used by the soccer player; [tex]E = 5100KJ = 5100000J[/tex]
  • Time; [tex]t = 2.0h = 7200s[/tex]

Power; [tex]P =\ ?[/tex]

Power is simply the amount of energy converted or transferred per unit time. It is expressed as:

[tex]Power = \frac{Energy\ converted }{time}[/tex]

We substitute our given values into the equation

[tex]Power = \frac{5100000J}{7200s}\\\\Power = 708.33J/s \\\\Power = 710J/s \ \ \ \ \ [ 2\ Significant\ Figures]\\\\Power = 710W[/tex]

Therefore, the average power produced by the soccer player is 710 Watts.

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Rewritten by : Barada

Final answer:

The formula for power is Energy/Time. After converting the player's energy use to joules and the time to seconds, the average power produced by the player during the match is calculated to be 708.33 Watts.

Explanation:

The average power produced by the player can be calculated using the formula Power = Energy/Time. The player's energy use is given in kilojoules (kJ) and the time is given in hours. Therefore, the energy must first be converted into joules (J) by multiplying by 1000 (1 kJ = 1000 J), and the time should be converted into seconds by multiplying by 3600 (1 hour = 3600 seconds).

So, using those conversions, we find that the player's energy use is 5100*1000 = 5100000J and the duration of the match is 2.0*3600 = 7200 s.

Therefore, the average power produced by the player is 5100000/7200 = 708.33 Watts.

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