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Answer :
Certainly! To find the potential energy of the bicycle at the top of the hill, we use the formula for gravitational potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy.
- [tex]\( m \)[/tex] is the mass of the object, which is 25 kg in this case.
- [tex]\( g \)[/tex] is the acceleration due to gravity. On Earth, this is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
- [tex]\( h \)[/tex] is the height of the hill, which is 3 meters.
Let's calculate the potential energy step-by-step:
1. Identify the values:
- Mass, [tex]\( m = 25 \, \text{kg} \)[/tex]
- Gravity, [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- Height, [tex]\( h = 3 \, \text{m} \)[/tex]
2. Plug these values into the formula:
[tex]\[
PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m}
\][/tex]
3. Perform the multiplication:
[tex]\[
PE = 25 \times 9.8 \times 3 = 735 \, \text{joules}
\][/tex]
So, the potential energy of the bicycle at the top of the hill is 735 joules.
The correct answer is [tex]\( 735 \, \text{J} \)[/tex].
[tex]\[ PE = m \times g \times h \][/tex]
Where:
- [tex]\( PE \)[/tex] is the potential energy.
- [tex]\( m \)[/tex] is the mass of the object, which is 25 kg in this case.
- [tex]\( g \)[/tex] is the acceleration due to gravity. On Earth, this is approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
- [tex]\( h \)[/tex] is the height of the hill, which is 3 meters.
Let's calculate the potential energy step-by-step:
1. Identify the values:
- Mass, [tex]\( m = 25 \, \text{kg} \)[/tex]
- Gravity, [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- Height, [tex]\( h = 3 \, \text{m} \)[/tex]
2. Plug these values into the formula:
[tex]\[
PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m}
\][/tex]
3. Perform the multiplication:
[tex]\[
PE = 25 \times 9.8 \times 3 = 735 \, \text{joules}
\][/tex]
So, the potential energy of the bicycle at the top of the hill is 735 joules.
The correct answer is [tex]\( 735 \, \text{J} \)[/tex].
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