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Answer :
To rewrite the exponential equation
[tex]$$2^x = 128$$[/tex]
in logarithmic form, recall the definition of logarithms: if
[tex]$$a^b = c,$$[/tex]
then it can be rewritten as
[tex]$$\log_a c = b.$$[/tex]
Applying this to the equation [tex]$2^x = 128$[/tex], where [tex]$a=2$[/tex], [tex]$b=x$[/tex], and [tex]$c=128$[/tex], we get
[tex]$$\log_2 128 = x.$$[/tex]
To check, note that [tex]$128 = 2^7$[/tex], so indeed
[tex]$$\log_2 128 = 7,$$[/tex]
which confirms that [tex]$x = 7$[/tex].
Thus, the logarithmic form of the equation is
[tex]$$\log_{2} 128 = x.$$[/tex]
[tex]$$2^x = 128$$[/tex]
in logarithmic form, recall the definition of logarithms: if
[tex]$$a^b = c,$$[/tex]
then it can be rewritten as
[tex]$$\log_a c = b.$$[/tex]
Applying this to the equation [tex]$2^x = 128$[/tex], where [tex]$a=2$[/tex], [tex]$b=x$[/tex], and [tex]$c=128$[/tex], we get
[tex]$$\log_2 128 = x.$$[/tex]
To check, note that [tex]$128 = 2^7$[/tex], so indeed
[tex]$$\log_2 128 = 7,$$[/tex]
which confirms that [tex]$x = 7$[/tex].
Thus, the logarithmic form of the equation is
[tex]$$\log_{2} 128 = x.$$[/tex]
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