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A rightward force is applied to a 67-kg object to move it across a rough surface at constant velocity. The object encounters a 15 N frictional force. What is the acceleration of the object?

Answer :

Answer:

ZERO acceleration

Explanation:

Object is moving at constant velocity (given in Q) <===so no acceleration !

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Rewritten by : Barada

Final answer:

The 67-kg object is moving at a constant velocity and hence its acceleration is 0 m/s². This is because the force moving it forward is equal to the frictional force, thus, cancelling each other out as per Newton's Second Law.

Explanation:

The subject of your question is Physics, specifically, the principles of Newton's Second Law and friction. In this case, the object is moving at a constant velocity. According to Newton's Second Law, when an object moves at a constant velocity, the net force acting on it is zero. This is because acceleration only occurs when there is a net force. The force moving the object forward is equal to the frictional force resisting its motion—hence, they cancel each other out. Therefore, the acceleration of the 67-kg object is 0 m/s².

Learn more about Newton's Second Law and Friction here:

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