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Marissa begins to solve the equation:



[tex]\frac{1}{2}(x-14) + 11 = \frac{1}{2} x - (x-4)[/tex]



Her work is correct and is shown below:



[tex]\begin{array}{c}

\frac{1}{2}(x-14) + 11 = \frac{1}{2} x - (x-4) \\

\frac{1}{2} x - 7 + 11 = \frac{1}{2} x - x + 4 \\

\frac{1}{2} x + 4 = -\frac{1}{2} x + 4

\end{array}[/tex]



When she subtracts 4, what is the result?



A. -1

B. 1

C. 0

D. 1

Answer :

- Subtract 4 from both sides of the equation: $\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4$.
- Simplify the equation: $\frac{1}{2}x = -\frac{1}{2}x$.
- Add $\frac{1}{2}x$ to both sides: $x = 0$.
- The value of x is $\boxed{0}$.

### Explanation
1. Understanding the Problem
Let's analyze the problem. We are given that Marissa correctly simplifies the equation to $\frac{1}{2}x + 4 = -\frac{1}{2}x + 4$. The question asks what results when she subtracts 4. It is implied that she subtracts 4 from both sides of the equation.

2. Subtracting 4 from both sides
Subtracting 4 from both sides of the equation $\frac{1}{2}x + 4 = -\frac{1}{2}x + 4$ gives us:$$\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4$$$$\frac{1}{2}x = -\frac{1}{2}x$$

3. Solving for x
Now, let's solve for $x$. Add $\frac{1}{2}x$ to both sides of the equation:$$\frac{1}{2}x + \frac{1}{2}x = -\frac{1}{2}x + \frac{1}{2}x$$$$x = 0$$

4. Final Answer
Therefore, when Marissa subtracts 4 from both sides and solves for $x$, the result is $x = 0$.

### Examples
Understanding how to solve linear equations is crucial in many real-world scenarios, such as calculating the amount of ingredients needed for a recipe or determining the distance traveled based on speed and time. In this case, solving the equation helps us find the value of x that satisfies the given conditions, which can be applied to various mathematical and practical problems.

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