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Answer :
The solubility of sodium nitrate at 95º C in g/ 100 mL of water is 448.21.
Equation :
To calculate the solubility
Using formula,
Solubility = mass of the compound / mass of the solvent
Thus,
Known data is :
mass of the compound, sodium nitrate = 84.994 g/mol
mass of the solvent, water = 18.015 g/mol
C = 84.994 g/mol / 18.015 g/mol
C = 4.718 g/mol
By the temperature 95ºC
So,
C = 4.718 g/mol x 95ºC
C = 448.21 g/ 100 mL
Solubility :
The maximum amount of the sample that will dissolve in a given amount of solvent at a given temperature is referred to as its solubility. Different substances have very different solubilities, which is a characteristic of a particular solute-solvent combination.
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