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Answer :
Final answer:
The true statements regarding the hypothesis testing conditions for the drilling sites are: F) the random condition is met because it is a simple random sample, C) the 10% condition is met because the sample size is less than 10% of the population, and E) the large counts condition is met as both np and n(1-p) are at least 10.
Explanation:
To analyze the statements provided, we should consider the conditions required for a hypothesis test regarding a population proportion using a sample. Here are the truths among the statements:
- F) Random: This condition is met because the sample is a simple random sample of 50 sites. A simple random sample means that every set of drilling sites has an equal chance of being selected, which meets the randomness condition for hypothesis testing.
- C) 10%: This condition is met because 50 < 10% of all possible drilling sites. Assuming the total number of drilling sites is in the thousands, the sample of 50 would be far less than 10% of the population, which adheres to the guideline that the sample size should be less than 10% of the population when using the binomial distribution results without needing a finite population correction factor.
- E) Large Counts: This condition is met because np = 20 and n(1
- p) = 30 are both at least 10. In a binomial distribution, np and nq (where q = 1-p, and p is the sample proportion) must both be at least 5 to approximate a normal distribution. Since these values are both well above 5, the large counts condition is satisfied.
The other statements A, B, and D are misleading or incorrect based on the information presented.
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