We appreciate your visit to The combined SAT scores for the students at a local high school are normally distributed with a mean of 1532 and a standard deviation of. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
14.67% of students from this school earn scores that fail to satisfy the admission requirement.
How to solve
To calculate the percentage of students from this school who earn scores that fail to satisfy the admission requirement, we can use the following steps:
Calculate the z-score for the admission requirement:
z = (admission requirement - mean) / standard deviation
z = (1871 - 1532) / 308
z = 1.108
Look up the probability that a standard normal variable will be less than 1.108 using a z-table. This probability is 0.1467.
Multiply the probability by 100% to convert it to a percentage:
percentage of students who fail to satisfy the admission requirement = 0.1467 * 100% = 14.67%
Therefore, 14.67% of students from this school earn scores that fail to satisfy the admission requirement.
Answer: 14.67%
Read more about probability here:
https://brainly.com/question/13604758
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