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A soccer player kicks a soccer ball at [tex]+10 \, \text{m/s}[/tex] at an angle of 60°.

What are the horizontal and vertical components of the velocity of the kick?

A. [tex]V_x = +5.00 \, \text{m/s}[/tex] and [tex]V_y = +8.66 \, \text{m/s}[/tex]
B. [tex]V_x = -8.66 \, \text{m/s}[/tex] and [tex]V_y = +5.00 \, \text{m/s}[/tex]
C. [tex]V_x = +8.66 \, \text{m/s}[/tex] and [tex]V_y = +5.00 \, \text{m/s}[/tex]
D. [tex]V_x = -5.00 \, \text{m/s}[/tex] and [tex]V_y = +8.66 \, \text{m/s}[/tex]

Answer :

Final answer:

The horizontal component of velocity is +5.00 m/s and the vertical component of velocity is +8.66 m/s.


Explanation:

When a soccer player kicks a ball at an angle, the velocity of the kick can be resolved into horizontal and vertical components. The horizontal component represents the motion of the ball along the x-axis and the vertical component represents the motion along the y-axis.

To find the horizontal component of velocity, we use the formula: V₂ = V × cos(θ), where V is the initial velocity and θ is the angle of kick. In this case, V = 10 m/s and θ = 60°. Substituting these values into the formula, we get: V₂ = 10 m/s × cos(60°) = 5 m/s.

Similarly, to find the vertical component of velocity, we use the formula: V₂ = V × sin(θ). Substituting the given values into the formula, we get: V₂ = 10 m/s × sin(60°) = 8.66 m/s.


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