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Answer :
To solve this problem, we need to analyze the scores and calculate the mean, median, and midrange to determine which answer choice is correct.
The given scores for the seven members of a women's golf team are: 68, 62, 60, 64, 70, 66, and another score which is 'ar'. However, we focus on the scores we have: 68, 62, 60, 64, 70, 66.
Let's calculate each statistical measure step-by-step:
1. Mean:
The mean is calculated by adding all the scores together and then dividing by the number of scores.
[tex]\[
\text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66}{6} = \frac{390}{6} = 65
\][/tex]
2. Median:
To find the median, we first arrange the scores in ascending order: 60, 62, 64, 66, 68, 70.
Since we have an even number of scores (6), the median is the average of the two middle numbers.
[tex]\[
\text{Median} = \frac{64 + 66}{2} = \frac{130}{2} = 65
\][/tex]
3. Midrange:
The midrange is calculated by taking the average of the smallest and largest numbers in the list.
[tex]\[
\text{Midrange} = \frac{60 + 70}{2} = \frac{130}{2} = 65
\][/tex]
According to our calculations, the mean, median, and midrange are all 65.
Now, let's review the answer choices:
- a. Mean = 64, median = 64, midrange = 64
- b. Mean = 65, median = 64, midrange = 66
- c. Mean = 66, median = 77, midrange = 65
- d. Mean = 66, median = 66, midrange = 66
Given our calculations (mean = 65, median = 65, midrange = 65), none of the listed choices exactly match the extracted numbers. Therefore, our computation suggests that the problem might have intended a different configuration or additional information about 'ar', which wasn't fully utilized in the outcome.
Thus, based on the given choices and our calculated statistical measures, none of the options perfectly align. However, closely examining our results, option B shows a matching mean while option A refers to completely different statistical results. It's a situation of recognizing the intended or nearest model to address.
The given scores for the seven members of a women's golf team are: 68, 62, 60, 64, 70, 66, and another score which is 'ar'. However, we focus on the scores we have: 68, 62, 60, 64, 70, 66.
Let's calculate each statistical measure step-by-step:
1. Mean:
The mean is calculated by adding all the scores together and then dividing by the number of scores.
[tex]\[
\text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66}{6} = \frac{390}{6} = 65
\][/tex]
2. Median:
To find the median, we first arrange the scores in ascending order: 60, 62, 64, 66, 68, 70.
Since we have an even number of scores (6), the median is the average of the two middle numbers.
[tex]\[
\text{Median} = \frac{64 + 66}{2} = \frac{130}{2} = 65
\][/tex]
3. Midrange:
The midrange is calculated by taking the average of the smallest and largest numbers in the list.
[tex]\[
\text{Midrange} = \frac{60 + 70}{2} = \frac{130}{2} = 65
\][/tex]
According to our calculations, the mean, median, and midrange are all 65.
Now, let's review the answer choices:
- a. Mean = 64, median = 64, midrange = 64
- b. Mean = 65, median = 64, midrange = 66
- c. Mean = 66, median = 77, midrange = 65
- d. Mean = 66, median = 66, midrange = 66
Given our calculations (mean = 65, median = 65, midrange = 65), none of the listed choices exactly match the extracted numbers. Therefore, our computation suggests that the problem might have intended a different configuration or additional information about 'ar', which wasn't fully utilized in the outcome.
Thus, based on the given choices and our calculated statistical measures, none of the options perfectly align. However, closely examining our results, option B shows a matching mean while option A refers to completely different statistical results. It's a situation of recognizing the intended or nearest model to address.
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