Answer :

In the given triangle JKL,

[tex]\begin{gathered} \angle J+\angle K+\angle L=180^{\circ} \\ 90^{\circ}+\frac{62^{\circ}}{2}+\angle L=180^{\circ} \\ 90^{\circ}+31^{\circ}+\angle L=180^{\circ} \\ \angle L=180^{\circ}-121^{\circ} \\ ^{}\angle L=59^{\circ} \end{gathered}[/tex]

Hence, option A is correct.

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