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A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable is needed to lower the cat/elevator pair with an acceleration of 2.00 m/s\(^2\) downwards?

Answer :

Final answer:

The force on the elevator cable needed to lower the cat/elevator pair with an acceleration of 2.00 m/s^2 downwards is 198.00 N.

Explanation:

To calculate the force on the elevator cable, we can use Newton's second law which states that force is equal to mass multiplied by acceleration. In this case, the total mass of the cat and elevator is 99.00 kg (2.00 kg + 97.00 kg). The acceleration given is 2.00 m/s2 downwards. Therefore, the force on the elevator cable would be:



Force = mass * acceleration



Force = 99.00 kg * 2.00 m/s2 = 198.00 N



So, the force on the elevator cable would need to be 198.00 N to lower the cat/elevator pair with an acceleration of 2.00 m/s2 downwards.

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Rewritten by : Barada

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

Given the following data:

  • Mass of cat = 2 kg
  • Mass of elevator = 97 kg
  • Acceleration = 2 [tex]m/s^2[/tex]

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

[tex]Total \;mass=2 + 97[/tex]

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]Force = mass \times acceleration[/tex]

Substituting the given parameters into the formula, we have;

[tex]Force = 99 \times 2[/tex]

Net force = 198 Newton

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