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5. Law of Acceleration:

A 1400 kg car is initially at rest. It is then accelerated by a 3000 N force for 10 seconds.

1. What is the car's acceleration?
2. How fast is it going after 10 seconds?

Answer :

The force acting on the car can be expressed as,

[tex]F=ma[/tex]

Plug in the known values,

[tex]\begin{gathered} 3000\text{ N=(1400 kg)a} \\ a=\frac{3000\text{ N}}{1400\text{ kg}}(\frac{1kgm/s^2}{1\text{ N}}) \\ =2.14m/s^2 \end{gathered}[/tex]

Thus, the acceleration of the car is 2.14 m/s2.

The final velocity of the car is given as,

[tex]v=u+at[/tex]

Substitute the known values,

[tex]\begin{gathered} v=0m/s+(2.14m/s^2)(10\text{ s)} \\ =21.4\text{ m/s} \end{gathered}[/tex]

Thus, the final velocity of the car is 21.4 m/s.

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