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Answer :
Answer:
C
Explanation:
Q=mcΔθ
Q=quantity of heat , m= mass of the storage rock
Δθ= temperature change.
m= Q/(cΔθ)
Q=5.4[tex]10^{7}[/tex]
Δθ=62°C-20°C
=42°C
c=0.21cal/g.°C
[tex]m=\frac{5.4*10^{7} }{0.21*42} \\\\m=6122448.98g\\[/tex]
m≈6100000g
m≈6100kg
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Final answer:
To find the mass of storage rock required to provide heat for a solar heated house, use the formula Q = mcΔT. Plugging in the given values, the correct answer is approximately 1,230 kg, option b.
Explanation:
The mass of storage rock needed to provide the heat lost by a solar heated house can be calculated using the formula:
Q = mcΔT, where Q is the heat lost, m is the mass of the rock, c is the specific heat capacity, and ΔT is the temperature change.
By plugging in the values given:
Q = 5.4 x 10⁷ cal
c = 0.21 cal/g⋅°C
ΔT = 62°C - 20°C = 42°C
The calculation yields a mass of approximately 1,230 kg, which corresponds to option b.
