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Answer :
Let [tex]$n$[/tex] be the first number. The sum of two consecutive numbers is given by
[tex]$$
n + (n+1) = 2n + 1.
$$[/tex]
We know that the sum is 157, so we set up the equation
[tex]$$
2n + 1 = 157.
$$[/tex]
Subtract 1 from both sides to isolate the term with [tex]$n$[/tex]:
[tex]$$
2n = 157 - 1 = 156.
$$[/tex]
Now, divide both sides by 2 to solve for [tex]$n$[/tex]:
[tex]$$
n = \frac{156}{2} = 78.
$$[/tex]
Thus, the first number is [tex]$78$[/tex], which corresponds to answer choice B.
[tex]$$
n + (n+1) = 2n + 1.
$$[/tex]
We know that the sum is 157, so we set up the equation
[tex]$$
2n + 1 = 157.
$$[/tex]
Subtract 1 from both sides to isolate the term with [tex]$n$[/tex]:
[tex]$$
2n = 157 - 1 = 156.
$$[/tex]
Now, divide both sides by 2 to solve for [tex]$n$[/tex]:
[tex]$$
n = \frac{156}{2} = 78.
$$[/tex]
Thus, the first number is [tex]$78$[/tex], which corresponds to answer choice B.
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