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Which equation can be used to solve for [tex]$x$[/tex]?

A. [tex]22x + 36 = 128[/tex]
B. [tex]5x - 19 = 128[/tex]
C. [tex]5x + 53 = 128[/tex]
D. [tex]22x - 36 = 128[/tex]

Solve for [tex]$x$[/tex]:
[tex]x = [/tex]
[tex]\square[/tex]

Answer :

To solve for [tex]\( x \)[/tex] in each equation and find which equation gives a valid solution, let's go through each one step-by-step:

1. Equation: [tex]\( 22x + 36 = 128 \)[/tex]

To solve for [tex]\( x \)[/tex], follow these steps:
- Subtract 36 from both sides: [tex]\( 22x = 128 - 36 \)[/tex]
- Simplify the right side: [tex]\( 22x = 92 \)[/tex]
- Divide both sides by 22: [tex]\( x = \frac{92}{22} \approx 4.18 \)[/tex]

2. Equation: [tex]\( 5x - 19 = 128 \)[/tex]

To solve for [tex]\( x \)[/tex], do the following:
- Add 19 to both sides: [tex]\( 5x = 128 + 19 \)[/tex]
- Simplify the right side: [tex]\( 5x = 147 \)[/tex]
- Divide both sides by 5: [tex]\( x = \frac{147}{5} = 29.4 \)[/tex]

3. Equation: [tex]\( 5x + 53 = 128 \)[/tex]

To solve for [tex]\( x \)[/tex], proceed as follows:
- Subtract 53 from both sides: [tex]\( 5x = 128 - 53 \)[/tex]
- Simplify the right side: [tex]\( 5x = 75 \)[/tex]
- Divide both sides by 5: [tex]\( x = \frac{75}{5} = 15.0 \)[/tex]

4. Equation: [tex]\( 22x - 36 = 128 \)[/tex]

To find [tex]\( x \)[/tex], carry out these steps:
- Add 36 to both sides: [tex]\( 22x = 128 + 36 \)[/tex]
- Simplify the right side: [tex]\( 22x = 164 \)[/tex]
- Divide both sides by 22: [tex]\( x = \frac{164}{22} \approx 7.45 \)[/tex]

Checking these solutions, the third equation [tex]\( 5x + 53 = 128 \)[/tex] gives a clean, whole number solution for [tex]\( x \)[/tex], which is [tex]\( x = 15.0 \)[/tex]. Therefore, [tex]\( 5x + 53 = 128 \)[/tex] is the correct equation for solving [tex]\( x \)[/tex] with a straightforward result.

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