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Answer :
Let's solve the given addition problems step-by-step using mental math techniques that can help you understand how to approach these kinds of questions.
1. Add these near doubles:
a. [tex]$350 + 360 = \square$[/tex]
- Both numbers are close to 350, and 360 is just 10 more than 350.
- So, you can quickly add 350 + 350 = 700.
- Then, add the extra 10 (from 360 being 10 more than 350).
- Total: 700 + 10 = 710
c. [tex]$920 + 900 = \square$[/tex]
- Both numbers are close to 900, with 920 being 20 more than 900.
- First, calculate 900 + 900 = 1800.
- Then, add the extra 20 from 920.
- Total: 1800 + 20 = 1820
e. [tex]$200 + 190 + 190 = \square$[/tex]
- Notice that 190 + 190 is close to adding 200 + 200.
- First, find 200 + 200 = 400.
- Since each 190 is 10 less than 200, subtract the 20 you added extra (10 for each 190).
- Then add the initial 200.
- Calculation: 400 - 20 + 200 = 580.
- Total: 580
g. [tex]$300 + 280 + 280 = \square$[/tex]
- Both 280s together can be thought of as two near 300s.
- Find 300 + 300 = 600 first.
- Since each 280 is 20 less than 300, subtract 20 for each 280.
- Therefore, subtract 40 from the extra you counted: 600 - 40 = 560.
- Then, add in the initial 300: 560 + 300 = 860.
- Total: 860
i. [tex]$790 + 800 = \square$[/tex]
- Both numbers are close to 800, with 790 being just 10 less than 800.
- Calculate 800 + 800 = 1600.
- Since 790 is 10 less than 800, subtract 10.
- Total: 1600 - 10 = 1590
k. [tex]$550 + 530 = \square$[/tex]
- Both numbers are close to 550, with 530 being 20 less than 550.
- Start by calculating 550 + 550 = 1100.
- Since 530 is 20 less than the original double-count, subtract 20.
- Total: 1100 - 20 = 1080
I hope this breakdown helps you see how using near doubles can make calculations quicker and easier!
1. Add these near doubles:
a. [tex]$350 + 360 = \square$[/tex]
- Both numbers are close to 350, and 360 is just 10 more than 350.
- So, you can quickly add 350 + 350 = 700.
- Then, add the extra 10 (from 360 being 10 more than 350).
- Total: 700 + 10 = 710
c. [tex]$920 + 900 = \square$[/tex]
- Both numbers are close to 900, with 920 being 20 more than 900.
- First, calculate 900 + 900 = 1800.
- Then, add the extra 20 from 920.
- Total: 1800 + 20 = 1820
e. [tex]$200 + 190 + 190 = \square$[/tex]
- Notice that 190 + 190 is close to adding 200 + 200.
- First, find 200 + 200 = 400.
- Since each 190 is 10 less than 200, subtract the 20 you added extra (10 for each 190).
- Then add the initial 200.
- Calculation: 400 - 20 + 200 = 580.
- Total: 580
g. [tex]$300 + 280 + 280 = \square$[/tex]
- Both 280s together can be thought of as two near 300s.
- Find 300 + 300 = 600 first.
- Since each 280 is 20 less than 300, subtract 20 for each 280.
- Therefore, subtract 40 from the extra you counted: 600 - 40 = 560.
- Then, add in the initial 300: 560 + 300 = 860.
- Total: 860
i. [tex]$790 + 800 = \square$[/tex]
- Both numbers are close to 800, with 790 being just 10 less than 800.
- Calculate 800 + 800 = 1600.
- Since 790 is 10 less than 800, subtract 10.
- Total: 1600 - 10 = 1590
k. [tex]$550 + 530 = \square$[/tex]
- Both numbers are close to 550, with 530 being 20 less than 550.
- Start by calculating 550 + 550 = 1100.
- Since 530 is 20 less than the original double-count, subtract 20.
- Total: 1100 - 20 = 1080
I hope this breakdown helps you see how using near doubles can make calculations quicker and easier!
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