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What is the domain of the function [tex]h[/tex]?

[tex]h(x) = \sqrt{x-7} + 5[/tex]

A. [tex]x \leq 5[/tex]

B. [tex]x \geq 5[/tex]

C. [tex]x \leq -7[/tex]

D. [tex]x \geq 7[/tex]

Answer :

To find the domain of the function [tex]\( h(x) = \sqrt{x - 7} + 5 \)[/tex], we need to determine the values of [tex]\( x \)[/tex] for which the function is defined.

1. Understand the function:
The function involves a square root. The expression inside the square root [tex]\( \sqrt{x - 7} \)[/tex] must be non-negative because we cannot take the square root of a negative number in the set of real numbers.

2. Set up the inequality:
To ensure that the expression under the square root is non-negative, solve the inequality:
[tex]\[
x - 7 \geq 0
\][/tex]

3. Solve for [tex]\( x \)[/tex]:
Add 7 to both sides of the inequality to isolate [tex]\( x \)[/tex]:
[tex]\[
x \geq 7
\][/tex]

4. Determine the domain:
The solution [tex]\( x \geq 7 \)[/tex] means that the function is defined for all values of [tex]\( x \)[/tex] that are greater than or equal to 7.

Therefore, the domain of the function [tex]\( h(x) = \sqrt{x - 7} + 5 \)[/tex] is [tex]\( x \geq 7 \)[/tex]. This corresponds to option D.

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