Answer :

The time it takes the frog to leap from flat ground at 6.32 m/s is 0.38 s

What is time?

Time is the duration of past, future, or present event.

To calculate the time it takes the frog to reach the maximum height, we use the formula below.

Formula:

  • t = usin∅/g............ Equation 1

Where:

  • t = Time it takes to reach the maximum height
  • u = Initial velocity
  • ∅ = Angle.
  • g = Acceleration due to gravity

From the question,

Given:

  • u = 6.32 m/s
  • ∅ = 36.3°
  • g = 9.8

Substitute these values into equation 1

  • t = 6.32×sin36.3/9.8
  • t = 0.38 s

Hence, the time it takes the frog to recah the amximum height is 0.38 s

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Rewritten by : Barada

Final answer:

To calculate the time at which the frog reaches its maximum height, you first calculate the initial vertical velocity, 6.32 m/s * sin(36.3 degrees) = 3.775 m/s. Then use the kinematic formula and insert final velocity as 0, initial as 3.775 m/s and acceleration due to gravity as -9.8 m/s^2 to find the time: 0.385 seconds.

Explanation:

This physics problem involves the application of the kinematics concepts of projectile motion. The initial velocity and angle of the frog's leap, and the force of gravity play important roles here. Since this problem is concerning the time at which the frog reaches its maximum height, we're essentially looking for the time at which vertical velocity equals zero (as the frog is midway through its leap and about to descend).

The vertical component of velocity can be calculated as follows: initial vertical velocity = initial total velocity * sin(Angle). Thus, 6.32 m/s * sin(36.3 degrees) = 3.775 m/s (using a calculator in degrees mode).

The time to reach the maximum height is then found using the following kinematic formula: time = (Final velocity - Initial velocity) / acceleration. Our final velocity is 0 (since this is the peak, or maximum height), and the acceleration due to gravity is -9.8 m/s^2 (negative because it's acting downwards). So the calculation becomes (0 - 3.775 m/s) / -9.8 m/s^2 = 0.385 seconds.

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