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Answer :
Final answer:
The normalized value at 6.1cm is calculated as 80/181 or 0.442. Theoretically, it should be (4.2/6.1)^2 or 0.47 since intensity should decrease with the square of the distance from the source. The difference between these values suggests small errors or other influencing factors.
Explanation:
Given that the signal value at 4.2 cm is 181 mV, we first normalize the data by dividing the signal value at 6.1 cm by 181 mV. Hence, the Normalized experimental value at 6.1 cm is 80/181 = 0.442.
Theoretically, based on the inverse square law, the intensity (flux) should decrease with the square of the distance from the source. Therefore, if we normalize this theoretical value to the measurement at 4.2 cm, the signal at 6.1 cm should be (4.2/6.1)^2 = 0.47.
Observing the results, while there is some difference between our experimental normalized value and the theoretically expected normalized value, the general trend follows the inverse square law. This indicates that the hypothesis may be correct, though factors like measurement error or other variables like the specific photometer used could affect results, specifically as the photometer is irrelevant to the relative values we're interested in.
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