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Answer :
Answer:
(viii) 116 ± 2.78 x 14.4√5
Step-by-step explanation:
The given data is
Sample size =n= 5
Calculated t- value= 2.4837
Mean= 116
Standard deviation= sd= 14.40486
The t - value from table with 4 d.f for ∝/2 is t∝/2 (n-1)= 2.776
The 95% confidence interval is calculated by
d` ± t∝/2 (n-1) *sd/√n
Putting the values
116 ± 2.776* 14.40486/√5
Comparing these values with the options Part viii gives the best answer.
(viii) 116 ± 2.78 x 14.4√5
2.776 when rounded gives 2.78 and 14.40486 when rounded gives 14.4
The rest are incorrect.
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The correct choice is option (viii) 116 ± 2.78 x 14.4/√5.
To calculate a 95% confidence interval for the true average birth weight of elephants, we use the formula for the confidence interval of the mean:
CI = mean ± (t-value * (sd / √n))
Given the data:
- mean (sample mean) = 116 kg
- standard deviation (sd) = 14.4 kg
- sample size (n) = 5
- t-value for 95% confidence interval with 4 degrees of freedom (df = n - 1) = 2.778
Now, we calculate the margin of error (ME):
ME = 2.778 * (14.4 / √5)
ME = 2.778 * (14.4 / 2.236)
ME ≈ 17.90
Then the 95% confidence interval (CI) is calculated as:
CI = 116 ± 17.90
So, the confidence interval is approximately (98.1, 133.9).
The correct choice among the provided options matches selection (viii) 116 ± 2.78 x 14.4/√5.