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Select the correct answer.

Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what's the force exerted by the snowmobile to accelerate? Use [tex]F = ma[/tex], where [tex]a = \frac{\Delta v}{t}[/tex].

A. 160 N
B. 168 N
C. 248 N
D. 280 N
E. 324 N

Answer :

To solve this problem, we'll need to find the force exerted by the snowmobile to accelerate from an initial velocity to a final velocity. We can use the formula [tex]\( F = ma \)[/tex], where [tex]\( F \)[/tex] is the force, [tex]\( m \)[/tex] is the mass, and [tex]\( a \)[/tex] is the acceleration.

Here's the step-by-step process:

1. Understand the given information:
- Initial velocity ([tex]\( v_i \)[/tex]) = 10 meters/second
- Final velocity ([tex]\( v_f \)[/tex]) = 16 meters/second
- Time taken to accelerate = 10 seconds
- Total mass ([tex]\( m \)[/tex]) = 280 kilograms

2. Calculate the acceleration ([tex]\( a \)[/tex]):
Acceleration is defined as the change in velocity over time. You can use the formula:
[tex]\[
a = \frac{{v_f - v_i}}{t}
\][/tex]
Substituting the given values:
[tex]\[
a = \frac{{16 \, \text{m/s} - 10 \, \text{m/s}}}{10 \, \text{s}} = \frac{6 \, \text{m/s}}{10 \, \text{s}} = 0.6 \, \text{m/s}^2
\][/tex]

3. Calculate the force ([tex]\( F \)[/tex]):
Now that we have the acceleration, we can find the force using the formula [tex]\( F = ma \)[/tex]:
[tex]\[
F = 280 \, \text{kg} \times 0.6 \, \text{m/s}^2 = 168 \, \text{N}
\][/tex]

The force exerted by the snowmobile to accelerate is 168 Newtons. Therefore, the correct answer is B. 168 N.

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