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Answer :
Sure, let's solve [tex]\( 235 \div 5 \)[/tex] step-by-step.
1. Set up the division:
[tex]\[
235 \div 5
\][/tex]
2. Divide 235 by 5:
- Begin with the first digit of 235, which is 2. Since 2 is smaller than 5, it cannot be divided by 5.
- Move to the next digit, making it 23 (the first two digits of 235).
- Determine how many times 5 goes into 23. 5 goes into 23 four times (since [tex]\(5 \times 4 = 20\)[/tex]), with a remainder of 3 (because [tex]\(23 - 20 = 3\)[/tex]).
3. Bring down the next digit:
- The next digit in 235 is 5, so bring it down next to the 3, making it 35.
- Determine how many times 5 goes into 35. 5 goes into 35 seven times (since [tex]\(5 \times 7 = 35\)[/tex]), with no remainder.
4. Combine the results of the division:
- The result from the above steps is 4 in the tens place and 7 in the units place. Putting these together, we get 47.
Hence,
[tex]\[
235 \div 5 = 47
\][/tex]
So, the answer is [tex]\( \boxed{47} \)[/tex].
1. Set up the division:
[tex]\[
235 \div 5
\][/tex]
2. Divide 235 by 5:
- Begin with the first digit of 235, which is 2. Since 2 is smaller than 5, it cannot be divided by 5.
- Move to the next digit, making it 23 (the first two digits of 235).
- Determine how many times 5 goes into 23. 5 goes into 23 four times (since [tex]\(5 \times 4 = 20\)[/tex]), with a remainder of 3 (because [tex]\(23 - 20 = 3\)[/tex]).
3. Bring down the next digit:
- The next digit in 235 is 5, so bring it down next to the 3, making it 35.
- Determine how many times 5 goes into 35. 5 goes into 35 seven times (since [tex]\(5 \times 7 = 35\)[/tex]), with no remainder.
4. Combine the results of the division:
- The result from the above steps is 4 in the tens place and 7 in the units place. Putting these together, we get 47.
Hence,
[tex]\[
235 \div 5 = 47
\][/tex]
So, the answer is [tex]\( \boxed{47} \)[/tex].
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