Answer :

Given:

[tex]\begin{gathered} m(\hat{AB})=58^{\circ} \\ m(\hat{DC})=110^{\circ} \end{gathered}[/tex]

To find: The angle

[tex]\angle BPC[/tex]

Explanation:

We know that,

[tex]\angle DPC=\frac{\hat{mAB}+\hat{mDC}}{2}[/tex]

On substitution we get,

[tex]\begin{gathered} \angle DPC=\frac{58+110}{2} \\ =\frac{168}{2} \\ \angle DPC=84^{\circ} \end{gathered}[/tex]

Using the linear pair,

[tex]\begin{gathered} \angle BPC+\angle DPC=180 \\ \angle BPC+84=180 \\ \angle BPC=180-84 \\ =96^{\circ} \end{gathered}[/tex]

Final answer:

The correct option is b.

[tex]\angle BPC=96^{\circ}[/tex]

Thanks for taking the time to read In the diagram below if arc AB measures 58 and arc DC measures 110 find the measure of BPC. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada