A block is pushed across a horizontal surface by a force [tex]F[/tex] with constant velocity. Given that [tex]F = 20 \, \text{N}[/tex], [tex]\theta = 30^\circ[/tex], and [tex]M = 10 \, \text{kg}[/tex], what is the magnitude of the normal force on the block?

A. 88 N
B. 94 N
C. 98 N
D. 108 N
E. 20 N

Question

14-11-2023
Physics

College

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A block is pushed across a horizontal surface by a force [tex]F[/tex] with constant velocity. Given that [tex]F = 20 \, \text{N}[/tex], [tex]\theta = 30^\circ[/tex], and [tex]M = 10 \, \text{kg}[/tex], what is the magnitude of the normal force on the block?

A. 88 N
B. 94 N
C. 98 N
D. 108 N
E. 20 N

Answer :

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Final answer:

In the given scenario, the magnitude of the normal force on a block pushed with a constant velocity across a horizontal surface is equal to its weight force, which is 98 N.

Explanation:

When a block is moving at a constant velocity, the net force acting on it is zero. In this case, the force being exerted on the block is counteracted by the friction acting against it. Thus, we have two forces to consider: the weight of the object (gravity) and the Normal Force (the force exerted by a surface that supports the weight of an object resting on it).

The equation for the gravitational force (weight) is F = m*g where m is the mass and g is gravity (approximately 9.81 m/s^2). Given that the block's mass (M) is 10 kg, the weight of the block is F = 10 kg * 9.81 m/s^2 = 98.1 N. Now, since there's no vertical motion (the block is not moving up or down), the normal force equals the weight. Therefore, the magnitude of the normal force on the block is 98 N.

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A block is pushed across a horizontal surface by a force [tex]F[/tex] with constant velocity. Given that [tex]F = 20 \, \text{N}[/tex], [tex]\theta = 30^\circ[/tex], and [tex]M = 10 \, \text{kg}[/tex], what is the magnitude of the normal force on the block?A. 88 N B. 94 N C. 98 N D. 108 N E. 20 N

Answer :

Final answer:

Explanation:

Learn more about Normal Force here:

Other Questions

A block is pushed across a horizontal surface by a force [tex]F[/tex] with constant velocity. Given that [tex]F = 20 \, \text{N}[/tex], [tex]\theta = 30^\circ[/tex], and [tex]M = 10 \, \text{kg}[/tex], what is the magnitude of the normal force on the block?

A. 88 N
B. 94 N
C. 98 N
D. 108 N
E. 20 N