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Answer :
To determine the number of liters of air contaminated to the extent of 100 ug/m^3 that must be collected, we need to consider the minimum amount of 25 ug required for analysis and the air-sampler operating at a rate of 2.5 LPM. Therefore, the correct answer is either 1 cubic meter.
Let's break down the information provided:
- The chemist requires a minimum of 25 ug for the analysis.
- The air-sampler operates at a rate of 2.5 LPM.
To calculate the number of liters of contaminated air that must be collected, we can use the following equation:
Volume of air (in liters) = (Concentration of contaminant (in ug/m³) × Time (in minutes)) / Flow rate (in LPM)
Using the given information, we can calculate the volume of air needed for the analysis:
Volume of air = (100 ug/m³ × Time (in minutes)) / 2.5 LPM
Now let's consider the answer choices provided and calculate the volume of air for each option:
1) 1 cubic meter collected for 25 minutes:
Volume of air = (100 ug/m³ × 25 minutes) / 2.5 LPM = 1000 liters
2) 250 liters collected for 100 minutes:
Volume of air = (100 ug/m³ × 100 minutes) / 2.5 LPM = 4000 liters
3) 100 liters collected for 25 minutes:
Volume of air = (100 ug/m³ × 25 minutes) / 2.5 LPM = 1000 liters
4) 25 liters collected for 100 minutes:
Volume of air = (100 ug/m³ × 100 minutes) / 2.5 LPM = 4000 liters
From the calculations above, we can see that options 1 and 3 both require 1000 liters of air to be collected, while options 2 and 4 require 4000 liters. Therefore, the correct answer is either 1 cubic meter collected for 25 minutes or 100 liters collected for 25 minutes, both resulting in 1000 liters of air to be collected.
Please note that the time required for the air-sampler to collect the specified volume of air may vary depending on its flow rate and the concentration of the contaminant.
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