We appreciate your visit to In a nuclear reactor each atom of uranium with an atomic mass of 235 u releases about 200 MeV when it fissions What is the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Answer:
0.002372187708 kg
Explanation:
Each atom of Uranium 235 releases 200 MeV = 200×10⁶×1.60218×10⁻¹⁹
= 200×1.60218×10⁻¹³ Joule
Number of atoms in a 2.6 kg sample mass = (2.6/0.235)×6.02214076×10²³
⇒Number of atoms in a 2.6 kg sample mass = 66.627×10²³ atoms
Change in energy = Change in mass / (speed of light)²
ΔE = Δmc²
⇒200×1.60218×10⁻¹³×66.627×10²³ = Δm×(3×10⁸)²
⇒Δm = 200×1.60218×10⁻¹³×66.627×10²³/(3×10⁸)²
⇒Δm = 2372.187708×10⁻⁶ kg
∴Change in mass = 0.002372187708 kg
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