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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented by the equation [tex]p=10000(1.04)^{-t}[/tex]. Which of these is an equivalent expression?

A. [tex]p=10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p=10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p=10000\left(\frac{26}{25}\right)^t[/tex]

D. [tex]p=10000\left(\frac{25}{1}\right)^t[/tex]

Answer :

To determine an equivalent expression for the population of the town, we start with the given equation:

[tex]\[ p = 10000(1.04)^{-t} \][/tex]

We need to find an expression that has the same result. Let's look at the base of the exponent, [tex]\(1.04^{-t}\)[/tex]:

1. Understanding the negative exponent: A negative exponent, such as [tex]\((1.04)^{-t}\)[/tex], means we take the reciprocal of the base. So, [tex]\((1.04)^{-1}\)[/tex] is the same as [tex]\(\frac{1}{1.04}\)[/tex].

2. Simplifying the reciprocal:
[tex]\[
\frac{1}{1.04} = \frac{1}{\frac{104}{100}} = \frac{100}{104}
\][/tex]

3. Simplifying the fraction:
- Divide the numerator and the denominator by their greatest common divisor, which is 4:
[tex]\[
\frac{100}{104} = \frac{25}{26}
\][/tex]

4. Writing the equivalent expression: Now, replacing [tex]\((1.04)^{-t}\)[/tex] with [tex]\((\frac{25}{26})^{t}\)[/tex], you get:

[tex]\[ p = 10000 \left(\frac{25}{26}\right)^t \][/tex]

This expression is equivalent to the original equation and matches one of the given options. Thus, the correct equivalent expression for the population is:

[tex]\[ p = 10000 \left(\frac{25}{26}\right)^t \][/tex]

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