College

We appreciate your visit to The weight of adults in a certain state follows an approximately normal distribution with a mean of 150 pounds and a standard deviation of 17. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The weight of adults in a certain state follows an approximately normal distribution with a mean of 150 pounds and a standard deviation of 17 pounds. According to the empirical rule, what percent of adults weigh more than 116 pounds?

Answer :

Answer:

97.5%

Step-by-step explanation:

Find the z-score:

z = (x − μ) / σ

z = (116 − 150) / 17

z = -2

According to the empirical rule, 95% of a population are between -2 and +2 standard deviations. That means that half of that, or 47.5%, are between -2 and 0 standard deviations. Since 50% are greater than 0 standard deviations, the total probability is 47.5% + 50%, or 97.5%.

P(Z > -2) = P(-2 < Z < 0) + P(Z > 0)

P(Z > -2) = 47.5% + 50%

P(Z > -2) = 97.5%

Thanks for taking the time to read The weight of adults in a certain state follows an approximately normal distribution with a mean of 150 pounds and a standard deviation of 17. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada