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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented using the equation [tex]p=10000(1.04)^{-t}[/tex]. Which of the following is an equivalent expression?

A. [tex]p=10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p=10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p=10000\left(\frac{26}{25}\right)^t[/tex]

D. [tex]p=10000\left(\frac{25}{1}\right)^t[/tex]

Answer :

To solve for an equivalent expression to the given equation [tex]\( p = 10000(1.04)^{-t} \)[/tex], let's break it down step by step:

1. Understand the Original Expression:
The original expression for the population is [tex]\( p = 10000(1.04)^{-t} \)[/tex].

2. Convert the Base to a Fraction:
We start by converting the base [tex]\( 1.04 \)[/tex] to a fraction. We can express [tex]\( 1.04 \)[/tex] as [tex]\( \frac{104}{100} \)[/tex], which simplifies to [tex]\( \frac{26}{25} \)[/tex].

3. Apply the Negative Exponent:
The expression [tex]\( (1.04)^{-t} \)[/tex] can be rewritten using the fraction:
[tex]\[
\left(\frac{26}{25}\right)^{-t}
\][/tex]

4. Simplify the Exponent:
Applying the rule for negative exponents, [tex]\(\left(\frac{a}{b}\right)^{-n} = \left(\frac{b}{a}\right)^{n}\)[/tex], we rewrite:
[tex]\[
\left(\frac{26}{25}\right)^{-t} = \left(\frac{25}{26}\right)^{t}
\][/tex]

5. Find the Equivalent Expression:
Now, substitute back into the original equation:
[tex]\[
p = 10000 \left(\frac{25}{26}\right)^{t}
\][/tex]

Thus, the equivalent expression is:
[tex]\[ p = 10000 \left(\frac{25}{26}\right)^{t} \][/tex]

This means the expression given by [tex]\( p = 10000\left(\frac{25}{26}\right)^t \)[/tex] is equivalent to the original expression.

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